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NEW QUESTION: 1
On Cisco IOS XR platforms using the EVC infrastructure, which command is used to enable a Layer 2 VPN subinterface?
A. interface gi0/0/0/0.10
switchport mode trunk
B. interface gi0/0/0/0.10
switchport mode tunnel dot1q-tunnel
C. interface gi0/0/0/0.10
bridge-group 10
D. interface gi0/0/0/0.10 l2transport
E. interface gi0/0/0/0.10
switchport access vlan 10
Answer: D
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 2
Which of the following is MOST useful when communicating risk to management?
A. Risk policy
B. Risk map
C. Maturity model
D. Audit report
Answer: A

NEW QUESTION: 3
Sie sind Datenbankentwickler für eine Anwendung, die auf einem Microsoft SQL Server 2014-Server gehostet wird. Die Datenbank enthält zwei Tabellen mit folgenden Definitionen:

Weltweite Kunden bestellen aus mehreren Ländern. Sie müssen das Land anzeigen, aus dem jeder Kunde die meisten Bestellungen aufgegeben hat.
Welche Transact-SQL-Abfrage verwenden Sie?
A. Wählen Sie c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER aus OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER JOIN (SELECT CustomerID, Versandland, RANK () OVER (PARTITION NACH CustomerIDORDER NACH COUNT (OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, Versandland) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER JOIN (SELECT customerID, ShippingCountry, RANK () OVER (PARTITION NACH CustomerIDORDER NACH OrderAmount DESC) AS RNKFROM OrdersGROUP NACH CustomerID, ShippingCountry) ASOON CustomerID = o.CustomerIDWHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK () OVER (PARTITION BY CustomerIDORDER BY COUNT (o.OrderAmount) ASC) AS RnkFROM Kunden-CINNER JOIN Bestellungen oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
Answer: B
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1