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NEW QUESTION: 1
米国に拠点を置く組織は、年内にヨーロッパ市場への事業拡大を計画しています。法律顧問は、拡大の結果として確立されなければならない追加の要件を調査しています。最善の行動方針は
A. 覚書を作成する
B. 定量的リスク評価を完了する
C. 従業員のプロビジョニングとプロビジョニング解除の手順を改訂する
D. データプライバシーに焦点を当てたセキュリティアンケートに回答します。
Answer: D

NEW QUESTION: 2
Scenario 2:
After completing the branch activation activities for all required branches, the network administrator attempts to test connectivity between the various branches and between the hubs and branches. The administrator notices a lack of connectivity despite being certain that configurations have been complete. The administrator also observed that several users are reporting intermittent connectivity to some of the applications they are accessing. Other users are reporting no access to these applications. Other users at some of the branches claim they cannot get to certain public resources. The administrator wants to ensure that all sites can talk to each other and all resources are accessible.
Exhibit.

A network administrator is trying to create multiple overlays on a single physical interface on an Edge. The administrator is able to bring up only a single overlay so far, but is having trouble with bringing up additional overlays.
What could be the possible reason?
A. The administrator does not have the right permission to create multiple overlays. The administrator needs to have an Operator-level privilege for this task.
B. Multiple overlays cannot be created on a single physical interface. Multiple physical interfaces are needed.
C. On the WAN overlay configuration, verify the IP address, next-hop, and the VLAN ID configuration.
D. The licensing does not support multiple overlays on a single physical interface.
Answer: D

NEW QUESTION: 3
Given:
ConcurrentMap <String, String> PartList = new ConcurrentMap<>();
Which fragment puts a key/value pair in partList without the responsibility of overwriting an existing key?
A. partList.out(key,"Blue Shirt");
B. partList.putAtomic(key,"Blue Shirt")
C. partList.putIfAbsent(key,"Blue Shirt");
D. if (!partList.containsKey(key)) partList.put (key,"Blue Shirt");
E. partList.putIfNotLocked (key,"Blue Shirt");
Answer: C
Explanation:
Explanation/Reference:
Explanation:
putIfAbsent(K key, V value)
If the specified key is not already associated with a value, associate it with the given value.
40
Reference:java.util.concurrent,Interface ConcurrentMap<K,V>