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NEW QUESTION: 1
注：この質問は同じシナリオを提示する一連の質問の一部です。連載の各質問には、記載されている目標を達成できる可能性のある固有の解決策が含まれています。他の人が正しい解決策を持っていないかもしれない間、いくつかの質問セットは複数の正しい解決策を持つかもしれません。
このセクションで質問に答えた後は、それに戻ることはできません。その結果、これらの質問はレビュー画面に表示されません。
Microsoft SQL Serverインスタンスをホストする仮想マシンのパフォーマンスを調整しています。
仮想マシンにはもともと4つのCPUコアがあり、現在は32個のCPUコアがあります。
SQL Serverインスタンスはデフォルト設定を使用し、db1という名前のOLTPデータベースを持ちます。 db1内の最大の表は、table1という名前のキー値ストア表です。
いくつかのレポートはPIVOTステートメントを使用し、table1の1億行を超える行にアクセスします。
レポートを実行すると、tempdbデータベース内のPFSページ2：1：1、2：2：1、2：3：1、および2：4：1でPAGELATCH_IO待機があることがわかります。
PAGELATCH_IO待機が発生しないようにする必要があります。
解決策：db1にファイルを追加します。
これは目標を達成していますか？
A. いいえ
B. はい
Answer: B
Explanation:
From SQL Server's perspective, you can measure the I/O latency from sys.dm_os_wait_stats. If you consistently see high waiting for PAGELATCH_IO, you can benefit from a faster I/O subsystem for SQL Server.
A cause can be poor design of your database - you may wish to split out data located on 'hot pages', which are accessed frequently and which you might identify as the causes of your latch contention. For example, if you have a currency table with a data page containing 100 rows, of which 1 is updated per transaction and you have a transaction rate of 200/sec, you could see page latch queues of 100 or more. If each page latch wait costs just 5ms before clearing, this represents a full half-second delay for each update. In this case, splitting out the currency rows into different tables might prove more performant (if less normalized and logically structured).
References:
https://www.mssqltips.com/sqlservertip/3088/explanation-of-sql-server-io-and-latches/

NEW QUESTION: 2
You are working with a table that has an XML column that contains information about books. Each book may have an associated price.
You need to write a query that returns each author on a separate row in XML format.
Which XML method should you use?
A. Exist()
B. Value()
C. Query()
D. Nodes()
Answer: D
Explanation:
The nodes() method is useful when you want to shred an xml data type instance into relational data. It allows you to identify nodes that will be mapped into a new row.
The result of the nodes() method is a rowset that contains logical copies of the original XML instances. In these logical copies, the context node of every row instance is set to one of the nodes identified with the query expression, so that subsequent queries can navigate relative to these context nodes.
Incorrect Answers:
A: The Value() method performs an XQuery against the XML and returns a value of SQL type. This method returns a scalar value.
C: The Query() method specifies an XQuery against an instance of the xml data type. The result is of xml type. The method returns an instance of untyped XML.
D: The Exists() method returns a bit that represents one of the following conditions:
1, representing True, if the XQuery expression in a query returns a nonempty result. That is, it returns at least one XML node.
0, representing False, if it returns an empty result.
NULL if the xml data type instance against which the query was executed contains NULL.
References: https://docs.microsoft.com/en-us/sql/t-sql/xml/nodes-method-xml-data-type?view=sql-server-2017

NEW QUESTION: 3
Which of the following commands replaces each occurrence of 'bob' in the file letter with
'Bob' and writes the result to the file newletter?
A. sed '/bob/Bob' letter > newletter
B. sed's/bob/Bob' letter > newletter
C. sed 's/bob/Bob/g' letter > newletter
D. sed s/bob/Bob/ letter < newletter
E. sed 's/bob, Bob/' letter > newletter
Answer: C

NEW QUESTION: 4
次の表に示す仮想マシンを含むAzureサブスクリプションがあります。

次の表に示すAzureポリシーを作成します。

以下の各ステートメントについて、ステートメントが真である場合は「はい」を選択します。それ以外の場合は、「いいえ」を選択します。
注：それぞれの正しい選択には1ポイントの価値があります。

Answer:
Explanation:

Explanation

References:
https://docs.microsoft.com/en-us/azure/governance/blueprints/concepts/resource-locking