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NEW QUESTION: 1
Excess moisture during holiday testing can cause erroneous indications by creating a path across the surface of the coating to pinholes previously detected, or directly to the signal return connection.
This is often referred to as:
A. juxtaposing.
B. telegraphing.
C. monitoring
D. transitioning.
Answer: B

NEW QUESTION: 2
Scenario:
CGE decided to virtualize its infrastructure workloads and provide a virtual solution to all end users. The infrastructure workloads include Delivery Controllers, StoreFront servers, License Servers, and Microsoft SQL Servers for databases.
How should the Hosted Shared servers be provisioned to meet the needs of the Back Office end-user group when only block storage is available on the shared storage of the Hypervisor?
A. By using Machine Creation Services (MCS)]
B. By manually installing the OS
C. By using Provisioning Services
D. By using cloned virtual machine (VM) templates
Answer: C

NEW QUESTION: 3

A. a maintenance plan
B. BACKUP TO URL
C. AlwaysOn Availability Groups
D. AlwaysOn failover clustering
Answer: A,B

NEW QUESTION: 4
Sie entwickeln eine Azure Cosmos DB-Lösung mithilfe der Azure Cosmos DB-SQL-API. Die Daten umfassen Millionen von Dokumenten. Jedes Dokument kann Hunderte von Eigenschaften enthalten.
Die Eigenschaften der Dokumente enthalten keine eindeutigen Werte für die Partitionierung. Azure Cosmos DB muss einzelne Container in der Datenbank skalieren, um die Leistungsanforderungen der Anwendung zu erfüllen, indem die Arbeitslast im Laufe der Zeit gleichmäßig auf alle Partitionen verteilt wird.
Sie müssen einen Partitionsschlüssel auswählen.
Welche zwei Partitionsschlüssel können Sie verwenden? Jede richtige Antwort bietet eine vollständige Lösung.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.
A. Ein einzelner Eigenschaftswert, der in den Dokumenten häufig vorkommt
B. Ein Wert, der den Sammlungsnamen enthält
C. ein einzelner Eigenschaftswert, der in den Dokumenten nicht häufig vorkommt
D. Ein Hash-Suffix, das an einen Eigenschaftswert angehängt wird
E. Eine Verkettung mehrerer Eigenschaftswerte mit einem angehängten zufälligen Suffix
Answer: D,E
Explanation:
Erläuterung:
Sie können einen Partitionsschlüssel bilden, indem Sie mehrere Eigenschaftswerte in einer einzelnen künstlichen partitionKey-Eigenschaft verketten. Diese Schlüssel werden als synthetische Schlüssel bezeichnet.
Eine andere mögliche Strategie, um die Arbeitslast gleichmäßiger zu verteilen, besteht darin, am Ende des Partitionsschlüsselwerts eine Zufallszahl anzufügen. Wenn Sie Elemente auf diese Weise verteilen, können Sie parallele Schreibvorgänge über Partitionen ausführen.
Hinweis: Es wird empfohlen, einen Partitionsschlüssel mit vielen unterschiedlichen Werten wie z. B. Hunderten oder Tausenden zu verwenden. Ziel ist es, Ihre Daten und Arbeitslast gleichmäßig auf die Elemente zu verteilen, die diesen Partitionsschlüsselwerten zugeordnet sind. Wenn eine solche Eigenschaft in Ihren Daten nicht vorhanden ist, können Sie einen synthetischen Partitionsschlüssel erstellen.
Verweise:
https://docs.microsoft.com/en-us/azure/cosmos-db/synthetic-partition-keys