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NEW QUESTION: 1
Examine the UserDir directives in this extract from /etc/httpd/conf/httpd.conf:
<IfModule mod_userdir.c> UserDirenabled user1 UserDirdisabled user1 UserDirpublic_html </IfModule>
The web server URL is http://host01.
A website server URL is http://host01.
A user attempts to access user1's webpages using this URL: httpd:/host01/~user1
Which statement describes the outcome?
A. The configuration produces an error upon web server startup, because the enabled and disabled directive conflict.
B. The occurrence of user1 in the list of enabled users allows access to the website contained in user1's public_html subdirectory, overriding the disabled directive.
C. Access is guaranteed because the UserDir public_html directive applies default access to all local users on the system, overriding the enabled of disabled directive.
D. The occurrence user1 in the list of disabled users causes an access denied error to the website contained in user1'1 public_html subdirecroty, overriding the enabled directive.
Answer: B

NEW QUESTION: 2
시계열에서 계절 변동의 영향을 제거하려면 원본 데이터는 다음과 같아야 합니다.
A. 계절적 요인에 의해 증가합니다.
B. 계절적 요인으로 곱한 값.
C. 계절적 요인에 의해 줄어든다.
D. 계절적 요인으로 나누어집니다.
Answer: D
Explanation:
Seasonal variations are common in many businesses. To remove the effect of seasonal variation from a time series, the original data with the four trends) is divided by the
seasonal norm.

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val<v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
B t1[]={3,2,4,1,5};
int t2[]={5,6,8,2,1};
vector<B> v1(10,0);
sort(t1, t1+5);
sort(t2, t2+5);
set_union(t1,t1+5,t2,t2+5,v1.begin());
for_each(v1.begin(), v1.end(), Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 1 2 3 4 5 6 8 0 0 0
B. 1 1 2 2 3 4 5 5 6 8
C. 1 2 3 4 5 6 8 2 1 0
D. compilation error
E. 3 2 4 1 5 6 8 2 1 0
Answer: D