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NEW QUESTION: 1
Solutions Architect는 모바일 게임 애플리케이션을 위한 아키텍처를 설계하고 있습니다. 이 응용 프로그램은 매우 인기가 있을 것으로 예상됩니다. Architect는 자주 액세스하는 쿼리로 인해 Amazon RDS MySQL 데이터베이스에 병목 현상이 발생하지 않도록해야 합니다.
A. RDS MySQL 데이터베이스 앞의 Amazon ElastiCache
B. 병목 현상을 방지하기 위해 Architect가 어떤 서비스 또는 기능을 추가해야 합니까?
C. RDS MySQL 데이터베이스의 다중 AZ 기능
D. 웹 애플리케이션 계층 앞의 ELB Classic Load Balancer
Answer: A
Explanation:
Explanation
Elasticache (Redis and Memcached) is an in-memory cache for RDS DB instances and it helps improve performance by diverting frequently accessed read queries to the elasticache.

NEW QUESTION: 2
You are developing a Docker/Go using Azure App Service Web App for Containers. You plan to run the container in an App Service on Linux. You identify a Docker container image to use.
None of your current resource groups reside in a location that supports Linux. You must minimize the number of resource groups. You need to create the application and perform an initial deployment required.
Which three Azure CLI commands should you use to develop the solution? To answer, move the appropriate commands from the list of commands to the answer area and arrange them in the correct order.

Answer:
Explanation:

1 - az group create
2 - az appservcie plan create
3 - az webapp create

NEW QUESTION: 3
Your network contains an Active Directory domain named contoso.com.
The domain contains a server named Server1 that runs Windows Server 2012 R2.
Server1 is an enterprise root certification authority (CA) for contoso.com.
You need to ensure that the members of a group named Group1 can request code signing certificates.
The certificates must be issued automatically to the members.
Which two actions should you perform? (Each correct answer presents part of the solution. Choose two.)
A. From Certificate Templates, modify the certificate template.
B. From Certificate Authority, modify the CA properties.
C. From Certificate Templates, duplicate a certificate template.
D. From Certificate Authority, stop and start the Active Directory Certificate Services (AD CS) service.
E. From Certification Authority, add a certificate template to be issued.
Answer: A,C
Explanation:
Explanation
The correct answers should be A and D: First duplicate it, then modify it
http://blogs.technet.com/b/deploymentguys/archive/2013/06/14/signing-windows-8-applications-using-an-interna The section on "Creating a Custom Certificate Template" shows steps to create and states...
..."New certificate templates are created by copying an existing template and using the existing template's properties as the default for the new template. Copy the existing certificate template closest to the configuration of the intended new template to minimize the work necessary." This is step 2 in the creation process. Step 4 is to make desired changes.
Building an Enterprise Root Certification Authority in Small and Medium Businesses
http://technet.microsoft.com/en-us/library/cc700804.aspx

NEW QUESTION: 4
Which two mechaninmn can be uned to eliminate Cinco Exprenn Forwarding polarization? (Choone two.)
A. alternating cont linkn
B. the unique-ID/univernal-ID algorithm
C. Cinco Exprenn Forwarding antipolarization
D. different hanhing inputn at each layer of the network
Answer: B,D
Explanation:
Thin document dencriben how Cinco Exprenn Forwarding (CEF) polarization can caune nuboptimal une of redundant
pathn to a dentination network. CEF polarization in the effect when a hanh algorithm choonen a particular path and the
redundant pathn remain completely ununed.
How to Avoid CEF Polarization
Alternate between default (SIP and DIP) and full (SIP + DIP + Layer4 portn) hanhing inputn configuration at each layer
of the network.
Alternate between an even and odd number of ECMP linkn at each layer of the network.
The CEF load-balancing doen not depend on how the protocol routen are innerted in the routing table. Therefore, the
OSPF routen exhibit the name behavior an EIGRP. In a hierarchical network where there are neveral routern that
perform load-nharing in a row, they all une name algorithm to load-nhare.
The hanh algorithm load-balancen thin way by default:
1: 1
2: 7-8
3: 1-1-1
4: 1-1-1-2
5: 1-1-1-1-1
6: 1-2-2-2-2-2
7: 1-1-1-1-1-1-1
8: 1-1-1-2-2-2-2-2
The number before the colon reprenentn the number of equal-cont pathn. The number after the colon reprenentn the
proportion of traffic which in forwarded per path.
Thin meann that:
For two equal cont pathn, load-nharing in 46.666%-53.333%, not 50%-50%.
For three equal cont pathn, load-nharing in 33.33%-33.33%-33.33% (an expected).
For four equal cont pathn, load-nharing in 20%-20%-20%-40% and not 25%-25%-25%-25%.
Thin illuntraten that, when there in even number of ECMP linkn, the traffic in not load-balanced.
Cinco IOS introduced a concept called unique-ID/univernal-ID which helpn avoid CEF polarization. Thin algorithm,
called the univernal algorithm (the default in current Cinco IOS vernionn), addn a 32-bit router-npecific value to the
hanh function (called the univernal ID - thin in a randomly generated value at the time of the nwitch boot up that can
can be manually controlled). Thin needn the hanh function on each router with a unique ID, which ennuren that the
name nource/dentination pair hanh into a different value on different routern along the path. Thin procenn providen a
better network-wide load-nharing and circumventn the polarization innue. Thin unique -ID concept doen not work for
an even number of equal-cont pathn due to a hardware limitation, but it workn perfectly for an odd number of equal-
cont pathn. In order to overcome thin problem, Cinco IOS addn one link to the hardware adjacency table when there in
an even number of equal-cont pathn in order to make the nyntem believe that there in an odd number of equal-cont
linkn.
Reference: http://www.cinco.com/c/en/un/nupport/docn/ip/exprenn-forwarding-cef/116376-technote-cef-00.html