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NEW QUESTION: 1
Examine this PeopleCode snippet:
Local Rowset &RSCUST, &RSSTUD;
&RSCUST = GetRowset(RECORD.CUST_TBL);
&RSSTUD = CreateRowset(RECORD.STUDENT_TBL);
&RSCUST.CopyTo(&RSSTUD, RECORD.CUST_TBL, RECORD.STUDENT_TBL);
Select the two correct statements. (Choose two.)
A. &RSCUST is a stand-alone rowset object based on the structure of the CUST_TBL record definition.
B. &RSSTUD is a stand-alone rowset object based on the structure of the STUDENT_TBL record definition.
C. &RSCUST is a rowset object that references the component buffer data for the CUST_TBL record.
D. &RSSTUD is a rowset object that references the component buffer data for the STUDENT_TBL record.
E. &RSCUST is a stand-alone rowset object that references the rows in PS_CUST_TBL.
F. &RSSTUD is a stand-alone rowset object that references the rows in PS_STUDENT_TBL.
Answer: B,C

NEW QUESTION: 2
Which of the following snort keywords is used to match a defined payload value?
A. ttl
B. id
C. content
D. msg
Answer: C

NEW QUESTION: 3
Amazon Simple Queue Service（SQS）キューからのメッセージを処理するインスタンスの自動シーリンググループがあります。
グループはキューのサイズに応じて調整されます。処理には、サードパーティのWebサービスの呼び出しが含まれます。
Webサービスが、ユーザーから受け取った失敗した呼び出しと繰り返された呼び出しの数について不平を言っています。
グループがスケールインすると、インスタンスの処理中にインスタンスが終了します。
不完全なプロセス試行の数を減らすために使用できる費用効果の高いソリューションはどれですか？
A. インスタンスで実行されているアプリケーションを変更して、タスクの処理中にそれ自体をAuto Scaling Standby状態にし、処理が完了すると自身をInServiceに戻します。
B. 最小および最大2つのインスタンスと、Webプロキシソフトウェアを実行するインスタンスを含む新しいAuto Scalingグループを作成します。
これらのウェブプロキシにHTTPトラフィックをルーティングするようにVPCルートテーブルを構成します。
C. Auto Scalingグループの最小サイズと最大サイズを増やし、スケーリングポリシーを変更して、動的スケーリングが少なくなるようにします。
D. インスタンスで実行されているアプリケーションを変更して、タスクの処理中に終了保護を有効にし、処理が完了したら無効にします。
Answer: D

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
#include <list>
#include <iostream>
using namespace std;
template<class T>
void print(T start, T end) {
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main()
{
int t1[] ={ 1, 7, 8, 4, 5 };
list<int> l1(t1, t1 + 5);
int t2[] ={ 3, 2, 6, 9, 0 };
list<int> l2(t2, t2 + 5);
l1.sort();
list<int>::iterator it = l2.begin();
it++; it++;
l1.splice(l1.end(),l2, it, l2.end());
print(l1.begin(), l1.end()); cout<<"Size:"<<l1.size()<<" ";
print(l2.begin(), l2.end()); cout<<"Size:"<<l2.size()<<endl;
return 0;
}
A. program outputs: 1 4 5 7 8 6 9 0 Size:8 3 2 6 9 0 Size:5
B. program outputs: 1 4 5 7 8 6 9 0 Size:8 3 2 Size:2
C. program outputs: 0 1 4 5 6 7 8 9 Size:8 3 2 6 9 0 Size:5
D. program outputs: 0 1 4 5 6 7 8 9 Size:8 3 2 Size:2
E. compilation error
Answer: B