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NEW QUESTION: 1

A. Option B
B. Option C
C. Option D
D. Option A
Answer: C
Explanation:
On R4 the DHCP IP address is not allowed for network 10.2.1.0/24 which clearly shows the problem lies on R4 & the problem is with DHCP
Case Study: 14
Ticket 14: IPv6 Routing Issue 1
Topology Overview (Actual Troubleshooting lab design is for below network design)
*Client Should have IP 10.2.1.3
*EIGRP 100 is running between switch DSW1 & DSW2
*OSPF (Process ID 1) is running between R1, R2, R3, R4
*Network of OSPF is redistributed in EIGRP
*BGP 65001 is configured on R1 with Webserver cloud AS 65002
*HSRP is running between DSW1 & DSW2 Switches
The company has created the test bed shown in the layer 2 and layer 3 topology exhibits.
This network consists of four routers, two layer 3 switches and two layer 2 switches.
In the IPv4 layer 3 topology, R1, R2, R3, and R4 are running OSPF with an OSPF process number 1.
DSW1, DSW2 and R4 are running EIGRP with an AS of 10. Redistribution is enabled where necessary.
R1 is running a BGP AS with a number of 65001. This AS has an eBGP connection to AS 65002 in the ISP's network.
Because the company's address space is in the private range.
R1 is also providing NAT translations between the inside (10.1.0.0/16 & 10.2.0.0/16) networks and outside
(209.65.0.0/24) network.
ASW1 and ASW2 are layer 2 switches.
NTP is enabled on all devices with 209.65.200.226 serving as the master clock source.
The client workstations receive their IP address and default gateway via R4's DHCP server.
The default gateway address of 10.2.1.254 is the IP address of HSRP group 10 which is running on DSW1 and DSW2.
In the IPv6 layer 3 topology R1, R2, and R3 are running OSPFv3 with an OSPF process number 6.
DSW1, DSW2 and R4 are running RIPng process name RIP_ZONE.
The two IPv6 routing domains, OSPF 6 and RIPng are connected via GRE tunnel running over the underlying IPv4 OSPF domain. Redistrution is enabled where necessary.
Recently the implementation group has been using the test bed to do a 'proof-of-concept' on several implementations. This involved changing the configuration on one or more of the devices. You will be presented with a series of trouble tickets related to issues introduced during these configurations.
Note: Although trouble tickets have many similar fault indications, each ticket has its own issue and solution.
Each ticket has 3 sub questions that need to be answered & topology remains same.
Question-1 Fault is found on which device,
Question-2 Fault condition is related to,
Question-3 What exact problem is seen & what needs to be done for solution
===============================================================================





NEW QUESTION: 2
与えられたコード断片:
class TechName {
String techName;
TechName (String techName) {
this.techName=techName;
}
}
and
List<TechName> tech = Arrays.asList (
new TechName("Java-"),
new TechName("Oracle DB-"),
new TechName("J2EE-")
);
Stream<TechName> stre = tech.stream();
//line n1
Java Oracle DB-J2EE-をプリントするために、どれがラインn1に挿入されるべきであるか?
A. stre.forEach(System.out::印刷);
B. stre.map.forEach(a-&gt; a.techName)(System.out::印刷);
C. stre.map.forEachOrdered(a-&gt; a)(System.out::印刷);
D. stre.forEachOrdered(System.out::印刷);
Answer: B

NEW QUESTION: 3
与えられた:
Item table
ID, INTEGER: PK
DESCRIP, VARCHAR(100)
PRICE, REAL
QUANTITY< INTEGER
And given the code fragment:
9. try {
10.Connection conn = DriveManager.getConnection(dbURL, username, password);
11.
String query = "Select * FROM Item WHERE ID = 110";
12.
Statement stmt = conn.createStatement();
13.
ResultSet rs = stmt.executeQuery(query);
14.while(rs.next()) {
15.System.out.println("ID:" + rs.getInt("Id"));
16.System.out.println("Description:" + rs.getString("Descrip"));
17.System.out.println("Price:" + rs.getDouble("Price"));
18. System.out.println(Quantity:" + rs.getInt("Quantity"));
19.}
20.
} catch (SQLException se) {
21.
System.out.println("Error");
22.
}
それを仮定しなさい:
必須のデータベース・ドライバーは、classpathで構成されます。
適切なデータベースはdbURL(userName)でアクセスできます、そして、passWord はそんざいする、
The SQLクエリは有効です。
結果は何ですか?
A. コードは、第110項に関する情報を印刷します。
B. 例外は、実行時に向けられます。
C. 編集は失敗します。
D. コードは、エラーを印刷します。
Answer: A


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