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NEW QUESTION: 1
On Cisco IOS XR platforms using the EVC infrastructure, which command is used to enable a Layer 2 VPN subinterface?
A. interface gi0/0/0/0.10
switchport access vlan 10
B. interface gi0/0/0/0.10
switchport mode tunnel dot1q-tunnel
C. interface gi0/0/0/0.10
switchport mode trunk
D. interface gi0/0/0/0.10 l2transport
E. interface gi0/0/0/0.10
bridge-group 10
Answer: D
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 2
Which of the following is MOST useful when communicating risk to management?
A. Risk map
B. Maturity model
C. Risk policy
D. Audit report
Answer: C

NEW QUESTION: 3
Sie sind Datenbankentwickler für eine Anwendung, die auf einem Microsoft SQL Server 2014-Server gehostet wird. Die Datenbank enthält zwei Tabellen mit folgenden Definitionen:

Weltweite Kunden bestellen aus mehreren Ländern. Sie müssen das Land anzeigen, aus dem jeder Kunde die meisten Bestellungen aufgegeben hat.
Welche Transact-SQL-Abfrage verwenden Sie?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK () OVER (PARTITION BY CustomerIDORDER BY COUNT (o.OrderAmount) ASC) AS RnkFROM Kunden-CINNER JOIN Bestellungen oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER JOIN (SELECT CustomerID, Versandland, RANK () OVER (PARTITION NACH CustomerIDORDER NACH COUNT (OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, Versandland) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER JOIN (SELECT customerID, ShippingCountry, RANK () OVER (PARTITION NACH CustomerIDORDER NACH OrderAmount DESC) AS RNKFROM OrdersGROUP NACH CustomerID, ShippingCountry) ASOON CustomerID = o.CustomerIDWHERE o.Rnk = 1
D. Wählen Sie c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER aus OrderAmount DESC
Answer: B
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1