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NEW QUESTION: 1
Refer to the exhibit.

The network diagram shows a video service provider. The IPTV video source is connected to R1, whereas the clients are connected to R6. Traffic flows from R1 to R6 both as unicast as well as multicast. Unicast traffic load is greater than multicast by several orders of magnitude. There are two paths from R1 to R6, each of them traverses through the R3 router. The path R1-R2-R3-R6 has a lower OSPF cost path compared to R1-R5-R4-R3-R6. The service provider took into account several design criteria and implemented TE tunnels with forwarding adjacency between R1 and R3 both from the perspective of load sharing as well as for fast reroute. Bringing up TE tunnels had the affect of dropping multicast traffic at the R3 router. On troubleshooting the issue, you noticed that the OSPF route to the source of multicast traffic was being learned over the TE tunnel, and this has caused the RPF check to fail.
Considering this problem, what are two solutions to prevent multicast traffic from being affected by the RPF check failing due to the TE tunnel? (Choose two.)
A. Create a static mroute on R3 with the RPF pointing to the TE tunnel.
B. Configure the TE tunnel to use autoroute announce as opposed to forwarding adjacency, and circumvent the RPF problem by using the multicast-intact command.
C. Enable PIM on the TE tunnel on both of the headend routers.
D. Use multitopology routing if the software supports it.
E. Use multicast-intact with forwarding adjacency.
F. Enable on the core facing links a new routing protocol such as another OSPF process or ISIS.
Answer: B,D

NEW QUESTION: 2
展示を参照してください。パケットがMaryからRobertに移動するとき、どの3つのデバイスがパケットの宛先MACアドレスを使用して転送パスを決定しますか？ （3つ選択してください。）

A. Hub1
B. ルーター2
C. Switch2
D. ルーター1
E. Switch3
F. Switch1
Answer: C,E,F
Explanation:
Switches use the destination MAC address information for forwarding traffic, while routers use the destination IP address information. Local Area Networks employ Layer 2 Switches and Bridges to forward and filter network traffic. Switches and Bridges operate at the Data Link Layer of the Open System Interconnect Model (OSI). Since Switches and Bridges operate at the Layer 2 they operate more intelligently than hubs, which work at Layer 1 (Physical Layer) of the OSI. Because the switches and bridges are able to listen to the traffic on the wire to examine the source and destination MAC address. Being able to listen to the traffic also allows the switches and bridges to compile a MAC address table to better filter and forward network traffic. To accomplish the above functions switches and bridges carry out the following tasks:
MAC address learning by a switch or a bridge is accomplished by the same method. The switch or bridge listens to each device connected to each of its ports and scan the incoming frame for the source MAC address. This creates a MAC address to port map that is cataloged in the switches/bridge MAC database. Another name for the MAC address table is content addressable memory orCAM table. When a switch or bridge is listening o the network traffic, it receives each frame and compares it to the MAC address table. By checking the MAC table the switch/ bridge are able o determine which port the frame came in on. If the frame is on the MAC table the frame is filtered or transmitted on only that port. If the switch determines that the frame is not on the MAC table, the frame is forwarded out to all ports except the incoming port.

NEW QUESTION: 3
Which statement is true regarding AutoPatch in the Oracle Applications Release 12 environment?
A. AutoPatch is platform-independent.
B. If all the prerequisite patches have not been applied, AutoPatch lists the missing prerequisites and continues with applying the current patch.
C. If language translation patches need to be applied in addition to the patch you are applying, AutoPatch notifies you.
D. There is a limit to the number of times AutoPatch can be restarted.
E. AutoPatch replaces the files in the product directory with the files in the patch directory in case the latter have the same version as theformer.
Answer: C