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NEW QUESTION: 1
Which JavaScript method is used to draw a circle on a canvas?
A. circle
B. ellipse
C. bezierCurveTo
D. arc
Answer: D

NEW QUESTION: 2
Which two statements about the utilization of IPv4 and IPv6 addresses in the Cisco ASA 9.x firewall access list configuration are true? (Choose two.)
A. Mixed IPv4 and IPv6 addresses cannot be used in the same access list for network object group
B. Mixed IPv4 and IPv6 addresses can be used in the same access list entry
C. Mixed IPv4 and IPv6 addresses cannot be used in the same access list
D. Mixed IPv4 and IPv6 addresses cannot be used in the same access list entry
E. Mixed IPv4 and IPv6 addresses can be used in the same access list for network object group
Answer: B,E

NEW QUESTION: 3
Refer to the exhibit.

All switches have default bridge priorities, and originate BPDUs with MAC addresses as indicated. The numbers shown are STP link metrics. Which two ports are in blocking state after STP converges? (Choose two.)
A. the port on switch SWD that connects to switch SWE
B. the port on switch SWD that connects to switch SWC
C. the port on switch SWB that connects to switch SWD
D. the port on switch SWF that connects to switch SWG
Answer: B,C
Explanation:
This is a scenario that wants you to demonstrate understanding of the Root switch and Root port election process. So, it's best to start with where the root switch will be and work down from there. It's setup nicely because the lowest MAC address switch starts at the top and then the lower priority/higher mac addresses move down the architecture. SWA wins the root election and of course all ports in SWA are forwarding. SWB introduces the possibility for a switching loop so it's important to understand which ports will be put into the blocking state. Since SWD is a higher MAC address it will end up with a blocked port connected to SWB to prevent a loop: and this is one of the correct answers. To prevent the possibility of another potential switching loop, SWD again ends up with the higher MAC address so blocking the link between D and C prevents a B/C/D switching loop.