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NEW QUESTION: 1
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten für diese Frage.
Sie haben eine Datenbank für ein Bankensystem. Die Datenbank enthält zwei Tabellen mit den Namen tblDepositAcct und tblLoanAcct, in denen Einlagen- und Darlehenskonten gespeichert sind. Beide Tabellen enthalten folgende Spalten:

Sie müssen die Gesamtzahl der Kunden ermitteln, die entweder Einlagenkonten oder Darlehenskonten haben, jedoch nicht beide Kontotypen.
Welche Transact-SQL-Anweisung sollten Sie ausführen?
A. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT (*) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
C. SELECT COUNT (DISTINCT L.CustNo) VON tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
D. SELECT COUNT (*) FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT D.CustNo) FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
F. SELECT COUNT (DISTINCT COALESCE (D.CustNo, L.CustNo)) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWhere
G. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
Answer: F
Explanation:
Erläuterung
SQL Server stellt den vollständigen Outer-Join-Operator FULL OUTER JOIN bereit, der alle Zeilen aus beiden Tabellen enthält, unabhängig davon, ob die andere Tabelle einen übereinstimmenden Wert hat oder nicht.
Betrachten Sie einen Join der Product-Tabelle und der SalesOrderDetail-Tabelle in ihren ProductID-Spalten. Die Ergebnisse zeigen nur die Produkte mit Kundenaufträgen. Der Operator ISO FULL OUTER JOIN gibt an, dass alle Zeilen aus beiden Tabellen in die Ergebnisse einbezogen werden sollen, unabhängig davon, ob die Tabellen übereinstimmende Daten enthalten.
Sie können eine WHERE-Klausel mit einem vollständigen Outer-Join einfügen, um nur die Zeilen zurückzugeben, bei denen keine übereinstimmenden Daten zwischen den Tabellen vorhanden sind. Die folgende Abfrage gibt nur die Produkte zurück, die keine übereinstimmenden Kundenaufträge haben, sowie die Kundenaufträge, die nicht mit einem Produkt übereinstimmen.
USE AdventureWorks2008R2;
GEHEN
- Das Schlüsselwort OUTER nach dem Schlüsselwort FULL ist optional.
SELECT p.Name, sod.SalesOrderID
AB Produktion.Produkt p
VOLLSTÄNDIGE AUSSENVERBINDUNG Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IST NULL
OR sod.ProductID IS NULL
ORDER BY p.Name;
Referenzen: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

NEW QUESTION: 2
次のうち、新しい情報セキュリティへの投資に最も適したものはどれですか？
A. 総合的な脅威分析の結果
B. プロジェクトの優先順位付けのシニアマネジメントの関与
C. リスクの予測される減少
D. 定義された主要なパフォーマンス指標（KPLS）
Answer: C

NEW QUESTION: 3
Which network does the IP address 220.100.100.100 belong to?
A. 220.100.100.0/24
B. 255.255.255.1/24
C. 220.100.100.1/24
D. 255.255.255.0/24
Answer: A

NEW QUESTION: 4
In a Dynamics CRM organization, you create a custom entity named Location.
You need to create a hierarchal set of location records.
What should you do?
A. Create a one-to-many (1:N) relationship between two different entities and set Hierarchical to Yes for the relationship definition.
B. Create a many-to-many (N:N) relationship between the same entity and set Hierarchical to Yes for the relationship definition.
C. Create a one-to-many (1:N) relationship between the same entity and set Hierarchical to Yes for the relationship definition.
D. Create a many-to-many (N:N) relationship between two different entities and set Hierarchical to Yes for the relationship definition.
Answer: C