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NEW QUESTION: 1
Oracle 12c Clusterwareによって管理されるアプリケーションのVIPに関して、どちらのステートメントが当てはまりますか？ （2つを選択してください）
A. アプリケーションが表示するメッセージを送信してDISPLAY変数を設定する場合は、アプリケーションVIPが必要です。
B. アプリケーションVIPは、crsctlユーティリティを使用して作成できます。
C. アプリケーションVIPは、crsctlユーティリティによって相互接続ネットワーク上に作成されます。
D. アプリケーションVIPは、VIPをホストしているノードに障害が発生した場合でも、存続しているクラスタノードにフェールオーバーしません。
E. アプリケーションVIPは、appvipcfgユーティリティによってデフォルトのネットワーク上に作成されます。
Answer: B,E
Explanation:
Explanation
B: Oracle 11.2 introduced appvipcfg utility for creating VIPs. From the GRID_HOME/bin directory run the appvipcfg command to create the application VIP. Oracle Clusterware assigns this VIP to a physical server in the cluster and will migrate the VIP to a surviving node in the cluster in the event of a server failure.
Example: appvipcfg create -network=1 -ip=192.168.20.111 -vipname=MyTestVIP -user=grid D: While you can add a VIP in the same way that you can add any other resource that Oracle Clusterware manages, Oracle recommends using the script Grid_home/bin/appvipcfg to create or delete an application VIP.

NEW QUESTION: 2
Before LANs existed, the most common data networks were:
A. MANs (metropolitan area networks).
B. WANs (wide area networks).
C. Mainframe networks.
D. Wireless networks.
Answer: C

NEW QUESTION: 3
Sie erstellen eine Tabelle mit den Spalten StudentCode, SubjectCode und Marks, um die Halbjahresnoten für die Schüler aufzuzeichnen. Die Tabelle enthält Noten von 50 Schülern für verschiedene Fächer.
Sie müssen sicherstellen, dass die obere Hälfte der Schüler, geordnet nach ihren Durchschnittsnoten, den Rang 1 und die übrigen Schüler den Rang 2 erhalten. Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION NACH SubjectCode ORDER NACH Marks DESC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
B. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) ALS Rang
FROM StudentMarks) tmp
WO Rang = 1
C. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Markiert ASC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
D. SELECT ID, Name, Markierungen,
DENSE_RANK () ÜBER (ORDER BY Markiert DESC) ALS Rang
VON StudentMarks
E. SELECT StudentCode as Code,
DENSE_RANK () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY ASC-Zeichen) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
G. SELECT StudentCode as Code,
RANG () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode as Code,
NTILE (2) OVER (BESTELLUNG NACH AVG (Marks) DESC) AS-Wert
VON StudentMarks
GROUP BY StudentCode
Answer: H

NEW QUESTION: 4



A. Option B
B. Option A
Answer: A