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NEW QUESTION: 1
You are asked to implement an interface that processes a batch of transaction objects and returns a discounted value for each transaction as a double primitive value.
Which interface can you use to accomplish the task?
A. DoubleFunction
B. ToDoubleFunction
C. DoubleSuppLier
D. DoubleConsumer
Answer: B

NEW QUESTION: 2

Refer to the exhibit. AMP cloud is configured to report AMP Connector scan events from windows machines belong to "Audi" group to FMC but the scanned events are not showing up in FMC, what could be the possible cause?
A. Incorrect group is selected for the events export in AMP cloud for FMC
B. DNS address is misconfigured on FMC
C. FMC is pointing to incorrect AMP cloud address
D. Event should be viewed as "Malware" event in FMC
E. AMP cloud is pointing to incorrect FMC address
F. Possible issue with certificate download from AMP cloud for FMC integration.
Answer: D

NEW QUESTION: 3

A. SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
C. SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
H. SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: B