C-SAC-2302 Practice Questions

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NEW QUESTION: 1
How do client/server systems differ from desktop CTI systems?
A. Desktop CTI systems cannot connect to as many telephone applications as can client/servers systems.
B. Desktop CTI systems can deliver only basic telephony, while client/servers systems can deliver extended telephony.
C. Desktop CTI systems cannot connect to ISDN service, but client/servers systems can.
D. Desktop CTI systems require a board in every PC, but client/servers systems require only one signal processing board.
Answer: A

NEW QUESTION: 2
Risk mitigation and risk reduction controls for providing information security are classified within three main categories, which of the following are being used?
A. Administrative, operational, and logical.
B. Physical, technical, and administrative.
C. Detective, corrective, and physical.
D. Preventive, corrective, and administrative.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Controls are put into place to reduce the risk an organization faces, and they come in three main flavors:
administrative, technical, and physical. Administrative controls are commonly referred to as "soft controls" because they are more management-oriented. Examples of administrative controls are security documentation, risk management, personnel security, and training. Technical controls (also called logical controls) are software or hardware components, as in firewalls, IDS, encryption, identification and authentication mechanisms. And physical controls are items put into place to protect facility, personnel, and resources. Examples of physical controls are security guards, locks, fencing, and lighting.
Incorrect Answers:
A: Neither preventive nor corrective are one of the three main categories of risk reduction controls.
B: Neither detective nor corrective are one of the three main categories of risk reduction controls.
D: Operational is not one of the three main categories of risk reduction controls.
References:
Harris, Shon, All In One CISSP Exam Guide, 6th Edition, McGraw-Hill, New York, 2013, p. 26

NEW QUESTION: 3



A. Option D
B. Option A
C. Option E
D. Option B
E. Option C
Answer: C
Explanation:
Section: (none)
Explanation
The code compiles fine.
java.lang.NullPointerException
because only one element of list is initialized : element [0]
elements [1] and [2] equals null
alte Begruendung:

Exception in thread "main" java.lang.ClassCastException: java.lang.String cannot be cast
to java.lang.Integer
at java.lang.Integer.compareTo(Integer.java:52)
at java.util.Arrays.binarySearch0(Arrays.java:1481)
at java.util.Arrays.binarySearch(Arrays.java:1423)
at searchtext.SearchText.main(SearchText.java:22)
Note:binarySearch
public static int binarySearch(char[] a,
char key)Searches the specified array of chars for the specified value using the binary
search algorithm. The array mustbe sorted (as by the sort method, above) prior to making
this call. If it is not sorted, the results are undefined. Ifthe array contains multiple elements
with the specified value, there is no guarantee which one will be found.
Parameters:
a - the array to be searched.
key - the value to be searched for.
Returns:
Indexof the search key, if it is contained in the list; otherwise, (-(insertion point) - 1). The
insertionpoint is defined as the point at which the key would be inserted into the list: the
index of the first elementgreater than the key, or list.size(), if all elements in the list are less
than the specified key. Note that thisguarantees that the return value will be >= 0 if and
only if the key is found.