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NEW QUESTION: 1
You are designing a form that uses a repeating grid to display office furniture items. Which two data sources can you use as a source for a repeating grid? (Choose two.)
A. A single value property that contains the data in a local list
B. A page list property that holds the data
C. Local data storage
D. A page group property that holds the data
Answer: B,D
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 2

A. SAP ERP
B. SAP Business One
C. SAP CRM
D. SAP Business All-In-One
Answer: B

NEW QUESTION: 3
Which of the following provides high availability? (Select TWO).
A. Zoneset
B. RAID0
C. Multipath
D. Snapshot
E. Hot spare
Answer: C,E

NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2014 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: D
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1